Parse-RPN
view release on metacpan or search on metacpan
return a with .1.3.6.1.2.1.25.3.3.1.2.768,.1.3.6.1.2.1.25.3.3.1.2.769,.1.3.6.1.2.1.25.3.3.1.2.771,.1.3.6.1.2.1.25.3.3.1.2.770
and b with 48,38,42,58
!!! becare, if you need to use : as a regex, you need to backslash to prevent overlap with new dictionary entry
SPLIT return the matched value WITHOUT the empty string of the beginning
aa bb SSPPLLIITT
return all splitted item of 'a' by the separator 'b'
'b' is a REGEX
!!! becare, if you need to use : as a regex, you need to backslash to prevent overlap with new dictionary entry
!!! if the split match on the beginning of string,
SPLIT return the matched value WITHOUT the empty string of the beginning
aa bb SSPPLLIITTII
return all splitted item of 'a' by the separator 'b'
'b' is a REGEX case insensitive
!!! becare, if you need to use : as a regex, you need to backslash to prevent overlap with new dictionary entry
!!! if the split match on the beginning of string,
SPLIT return the matched value WITHOUT the empty string of the beginning
aa bb PPAATT
return one or more occurance of 'b' in 'a'
'b' is a REGEX
!!! becare, if you need to use : as a regex, you need to backslash to prevent overlap with new dictionary entry
aa bb PPAATTII
return one or more occurance of 'b' in 'a'
'b' is a REGEX case insensitive
lib/Parse/RPN.pm view on Meta::CPAN
$var{ $v2 } = \@T2;
my @ret;
return \@ret, 5, 0;
};
=head2 a b SPLIT
return all splitted item of 'a' by the separator 'b'
'b' is a REGEX
!!! becare, if you need to use : as a regex, you need to backslash to prevent overlap with new dictionary entry
!!! if the split match on the beginning of string,
SPLIT return the matched value WITHOUT the empty string of the beginning
=cut
$dict{SPLIT} = sub {
my $work1 = shift;
my $a = pop @{ $work1 };
my $b = pop @{ $work1 };
my @r = grep /[^(^$)]/, split /$a/, $b;
my @ret;
push @ret, @r;
return \@ret, 2, 0;
};
=head2 a b SPLITI
return all splitted item of 'a' by the separator 'b'
'b' is a REGEX case insensitive
!!! becare, if you need to use : as a regex, you need to backslash to prevent overlap with new dictionary entry
!!! if the split match on the beginning of string,
SPLIT return the matched value WITHOUT the empty string of the beginning
=cut
$dict{SPLITI} = sub {
my $work1 = shift;
my $a = pop @{ $work1 };
my $b = pop @{ $work1 };
my @r = grep /[^(^$)]/, split /$a/i, $b;
my @ret;
( run in 2.769 seconds using v1.01-cache-2.11-cpan-71847e10f99 )