IO-ReadPreProcess
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.# For loop just to see how long this takes.
.let iter := 10000
.echo Before for loop containing one arith statement - iterations \v{iter}
.let j := 0
.for -i0 i := 0 ;; i < iter ;; i++
.noop
.let j := j + i
.done
.echo After for, j = \v{j}
( run in 1.827 second using v1.01-cache-2.11-cpan-71847e10f99 )