Crypt-Bear
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src/rsa/rsa_i15_keygen.c view on Meta::CPAN
*/
static uint32_t
invert_pubexp(uint16_t *d, const uint16_t *m, uint32_t e, uint16_t *t)
{
uint16_t *f;
uint32_t r;
f = t;
t += 1 + ((m[0] + 15) >> 4);
/*
* Compute d = 1/e mod m. Since p = 3 mod 4, m is odd.
*/
br_i15_zero(d, m[0]);
d[1] = 1;
br_i15_zero(f, m[0]);
f[1] = e & 0x7FFF;
f[2] = (e >> 15) & 0x7FFF;
f[3] = e >> 30;
r = br_i15_moddiv(d, f, m, br_i15_ninv15(m[1]), t);
/*
* We really want d = 1/e mod p-1, with p = 2m. By the CRT,
* the result is either the d we got, or d + m.
*
* Let's write e*d = 1 + k*m, for some integer k. Integers e
* and m are odd. If d is odd, then e*d is odd, which implies
* that k must be even; in that case, e*d = 1 + (k/2)*2m, and
* thus d is already fine. Conversely, if d is even, then k
* is odd, and we must add m to d in order to get the correct
* result.
*/
br_i15_add(d, m, (uint32_t)(1 - (d[1] & 1)));
return r;
}
/*
* Swap two buffers in RAM. They must be disjoint.
*/
static void
bufswap(void *b1, void *b2, size_t len)
{
size_t u;
unsigned char *buf1, *buf2;
buf1 = b1;
buf2 = b2;
for (u = 0; u < len; u ++) {
unsigned w;
w = buf1[u];
buf1[u] = buf2[u];
buf2[u] = w;
}
}
/* see bearssl_rsa.h */
uint32_t
br_rsa_i15_keygen(const br_prng_class **rng,
br_rsa_private_key *sk, void *kbuf_priv,
br_rsa_public_key *pk, void *kbuf_pub,
unsigned size, uint32_t pubexp)
{
uint32_t esize_p, esize_q;
size_t plen, qlen, tlen;
uint16_t *p, *q, *t;
uint16_t tmp[TEMPS];
uint32_t r;
if (size < BR_MIN_RSA_SIZE || size > BR_MAX_RSA_SIZE) {
return 0;
}
if (pubexp == 0) {
pubexp = 3;
} else if (pubexp == 1 || (pubexp & 1) == 0) {
return 0;
}
esize_p = (size + 1) >> 1;
esize_q = size - esize_p;
sk->n_bitlen = size;
sk->p = kbuf_priv;
sk->plen = (esize_p + 7) >> 3;
sk->q = sk->p + sk->plen;
sk->qlen = (esize_q + 7) >> 3;
sk->dp = sk->q + sk->qlen;
sk->dplen = sk->plen;
sk->dq = sk->dp + sk->dplen;
sk->dqlen = sk->qlen;
sk->iq = sk->dq + sk->dqlen;
sk->iqlen = sk->plen;
if (pk != NULL) {
pk->n = kbuf_pub;
pk->nlen = (size + 7) >> 3;
pk->e = pk->n + pk->nlen;
pk->elen = 4;
br_enc32be(pk->e, pubexp);
while (*pk->e == 0) {
pk->e ++;
pk->elen --;
}
}
/*
* We now switch to encoded sizes.
*
* floor((x * 17477) / (2^18)) is equal to floor(x/15) for all
* integers x from 0 to 23833.
*/
esize_p += MUL15(esize_p, 17477) >> 18;
esize_q += MUL15(esize_q, 17477) >> 18;
plen = (esize_p + 15) >> 4;
qlen = (esize_q + 15) >> 4;
p = tmp;
q = p + 1 + plen;
t = q + 1 + qlen;
tlen = ((sizeof tmp) / sizeof(uint16_t)) - (2 + plen + qlen);
/*
( run in 1.018 second using v1.01-cache-2.11-cpan-5a3173703d6 )