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Thanks to all for the responses,
more comments below...

Niall O Broin wrote:
> On Fri, Aug 16, 2002 at 05:26:33PM +0100, Padraig Brady wrote:
> 
> 
>>How can I repeat a string an arbitrary number
>>of times in bash/sed/...
>>
>>I.E. I'm missing the repeat in the following:
>>
>>STRING="> "
>>NUMBER=3
>>PREFIX=repeat $STRING $NUMBER
>>echo $PREFIX
>>
>>Pádraig.
>>p.s. I know how to do it with loops.
> 
> 
> Well, here's a solution using seq and sed - IMHO its a rather dim solution
> and it definitely dies if STRING contains / (and probably has other ways to
> die too) and a bash loop would certainly be faster, but you know how to do
> it with loops :-)
> 
> PREFIX=seq -s "" $NUMBER|sed "s/./$STRING/g"OA

clever. A bit more robust is:
#first param is number of
#times to repeat second param
#
#e.g. quote=`repeat 3 '> '`
repeat() {
     seq -s , $1 | sed "s¬[0-9]\{1,\}[,]*¬$2¬g"
}

btw loops in bash are shit slow! see:
http://www.iol.ie/~padraiga/readline/

> And while we're on silly bash questions, is there a way of getting the exit
> status of a command without using $? i.e. can I do something like
> 
> result = some_magic_way_of_quoting(command)
> 
> instead of
> 
> command
> result=$?
> 
> Note that I'm not looking for backtick or $() substitution, nor arithmetic
> evaluation as with $[]

I don't think this is possible.

thanks,
Pádraig.


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