Algorithm-BIT-XS
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lib/Algorithm/BIT2D/XS.pm view on Meta::CPAN
package Algorithm::BIT2D::XS;
use 5.014000;
use strict;
use warnings;
our $VERSION = '0.003';
use Algorithm::BIT::XS;
sub new {
my ($class, $n, $m) = @_;
create($n, $m);
}
sub get {
my ($b, $i1, $i2) = @_;
$b->query($i1, $i2) + $b->query($i1 - 1, $i2 - 1)
- $b->query($i1 - 1, $i2) - $b->query($i1, $i2 - 1);
}
sub set {
my ($b, $i1, $i2, $value) = @_;
$b->update($i1, $i2, $value - $b->get($i1, $i2))
}
1;
__END__
=encoding utf-8
=head1 NAME
Algorithm::BIT2D::XS - 2D Binary indexed trees / Fenwick trees
=head1 SYNOPSIS
use Algorithm::BIT2D::XS;
my $bit = Algorithm::BIT2D::XS->new(100, 100);
$bit->update(1, 2, 5); # bit[1][2] += 5
$bit->update(3, 3, 6); # bit[3][3] += 6
say 'bit[1..2][1..10] == ', $bit->query(2, 10); # 5
say 'bit[1..3][1..2] == ', $bit->query(3, 2); # 5
say 'bit[1..20][1..10] == ', $bit->query(20, 10); # 11
$bit->update(3, 1, 10); # bit[3][1] += 10
say 'bit[1..3][1..3] == ', $bit->query(3, 3); # 21
say 'bit[3][3] == ', $bit->get(3, 3); # 6
$bit->set(3, 3, 10); # bit[3][3] = 10
say 'bit[3][3] == ', $bit->get(3, 3); # 10
$bit->clear;
say 'bit[1..100][1..10] == ', $bit->query(100, 10); # 0
$bit->set(100, 10, 5);
say 'bit[1..100][1..10] == ', $bit->query(100, 10); # 5
=head1 DESCRIPTION
A binary indexed tree is a data structure similar to an array of integers.
The two main operations are updating an element and calculating a
prefix sum, both of which run in time logarithmic in the size of the tree.
=over
=item Algorithm::BIT2D::XS->B<new>(I<$n>, I<$m>)
Create a new 2D binary indexed tree of length I<$n> x I<$m>. As binary
indexed trees are 1-indexed, its indexes are [1..I<$n>][1..I<$m>].
It is initially filled with zeroes.
=item $bit->B<clear>()
Clears the binary indexed tree (sets all elements to 0).
=item $bit->B<query>(I<$i1>, I<$i2>)
Returns the rectangle sum from I<$bit>[1][1] to I<$bit>[I<$i1>][I<$i2>].
=item $bit->B<update>(I<$i1>, I<$i2>, I<$value>)
Adds I<$value> to I<$bit>[I<$i1>][I<$i2>].
=item $bit->B<get>(I<$i1>, I<$i2>)
Returns the value of I<$bit>[I<$i1>][I<$i2>].
=item $bit->B<set>(I<$i1>, I<$i2>, I<$value>)
Sets I<$bit>[I<$i1>][I<$i2>] to I<$value>.
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