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cppjieba/deps/limonp/test/gtest/include/gtest/gtest-printers.h  view on Meta::CPAN

 public:
  // This default version is called when kTypeKind is kOtherType.
  static void PrintValue(const T& value, ::std::ostream* os) {
    PrintBytesInObjectTo(reinterpret_cast<const unsigned char*>(&value),
                         sizeof(value), os);
  }
};

// We print a protobuf using its ShortDebugString() when the string
// doesn't exceed this many characters; otherwise we print it using
// DebugString() for better readability.
const size_t kProtobufOneLinerMaxLength = 50;

template <typename T>
class TypeWithoutFormatter<T, kProtobuf> {
 public:
  static void PrintValue(const T& value, ::std::ostream* os) {
    const ::testing::internal::string short_str = value.ShortDebugString();
    const ::testing::internal::string pretty_str =
        short_str.length() <= kProtobufOneLinerMaxLength ?
        short_str : ("\n" + value.DebugString());
    *os << ("<" + pretty_str + ">");
  }
};

template <typename T>
class TypeWithoutFormatter<T, kConvertibleToInteger> {
 public:
  // Since T has no << operator or PrintTo() but can be implicitly
  // converted to BiggestInt, we print it as a BiggestInt.
  //
  // Most likely T is an enum type (either named or unnamed), in which
  // case printing it as an integer is the desired behavior.  In case
  // T is not an enum, printing it as an integer is the best we can do
  // given that it has no user-defined printer.
  static void PrintValue(const T& value, ::std::ostream* os) {
    const internal::BiggestInt kBigInt = value;
    *os << kBigInt;
  }
};

// Prints the given value to the given ostream.  If the value is a
// protocol message, its debug string is printed; if it's an enum or
// of a type implicitly convertible to BiggestInt, it's printed as an
// integer; otherwise the bytes in the value are printed.  This is
// what UniversalPrinter<T>::Print() does when it knows nothing about
// type T and T has neither << operator nor PrintTo().
//
// A user can override this behavior for a class type Foo by defining
// a << operator in the namespace where Foo is defined.
//
// We put this operator in namespace 'internal2' instead of 'internal'
// to simplify the implementation, as much code in 'internal' needs to
// use << in STL, which would conflict with our own << were it defined
// in 'internal'.
//
// Note that this operator<< takes a generic std::basic_ostream<Char,
// CharTraits> type instead of the more restricted std::ostream.  If
// we define it to take an std::ostream instead, we'll get an
// "ambiguous overloads" compiler error when trying to print a type
// Foo that supports streaming to std::basic_ostream<Char,
// CharTraits>, as the compiler cannot tell whether
// operator<<(std::ostream&, const T&) or
// operator<<(std::basic_stream<Char, CharTraits>, const Foo&) is more
// specific.
template <typename Char, typename CharTraits, typename T>
::std::basic_ostream<Char, CharTraits>& operator<<(
    ::std::basic_ostream<Char, CharTraits>& os, const T& x) {
  TypeWithoutFormatter<T,
      (internal::IsAProtocolMessage<T>::value ? kProtobuf :
       internal::ImplicitlyConvertible<const T&, internal::BiggestInt>::value ?
       kConvertibleToInteger : kOtherType)>::PrintValue(x, &os);
  return os;
}

}  // namespace internal2
}  // namespace testing

// This namespace MUST NOT BE NESTED IN ::testing, or the name look-up
// magic needed for implementing UniversalPrinter won't work.
namespace testing_internal {

// Used to print a value that is not an STL-style container when the
// user doesn't define PrintTo() for it.
template <typename T>
void DefaultPrintNonContainerTo(const T& value, ::std::ostream* os) {
  // With the following statement, during unqualified name lookup,
  // testing::internal2::operator<< appears as if it was declared in
  // the nearest enclosing namespace that contains both
  // ::testing_internal and ::testing::internal2, i.e. the global
  // namespace.  For more details, refer to the C++ Standard section
  // 7.3.4-1 [namespace.udir].  This allows us to fall back onto
  // testing::internal2::operator<< in case T doesn't come with a <<
  // operator.
  //
  // We cannot write 'using ::testing::internal2::operator<<;', which
  // gcc 3.3 fails to compile due to a compiler bug.
  using namespace ::testing::internal2;  // NOLINT

  // Assuming T is defined in namespace foo, in the next statement,
  // the compiler will consider all of:
  //
  //   1. foo::operator<< (thanks to Koenig look-up),
  //   2. ::operator<< (as the current namespace is enclosed in ::),
  //   3. testing::internal2::operator<< (thanks to the using statement above).
  //
  // The operator<< whose type matches T best will be picked.
  //
  // We deliberately allow #2 to be a candidate, as sometimes it's
  // impossible to define #1 (e.g. when foo is ::std, defining
  // anything in it is undefined behavior unless you are a compiler
  // vendor.).
  *os << value;
}

}  // namespace testing_internal

namespace testing {
namespace internal {

// UniversalPrinter<T>::Print(value, ostream_ptr) prints the given